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44 votes
Factor completely 81x8 − 1. (9x4 − 1)(9x4 1) (3x2 − 1)(3x2 1)(9x4 − 1) (3x2 − 1)(3x2 1)(9x4 1) (3x2 − 1)(3x2 1)(3x2 1)(3x2 1).

User Jnforja
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2 Answers

11 votes
11 votes

Answer:

The answer is (3x^2 - 1)(3x^2 + 1)(9x^4 + 1).

Explanation:

User Matthieu Rouif
by
2.8k points
14 votes
14 votes

Answer:

(3x^2 - 1)(3x^2 + 1)(9x^4 + 1).

Explanation:

Using the identity for the difference of 2 squares;

a^2 - b^2 = (a - b)(a + b)

we put a^2 = 81x^8 and b^2 = 1 giving

a = 9x^4 and b = 1, so:

81x^8 − 1 = (9x^4 - 1)(9x^4 + 1)

Applying the difference of 2 squares to 9x^4 - 1:

= (3x^2 - 1)(3x^2 + 1)(9x^4 + 1).

User PersyJack
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2.8k points