Question

in the year 2001, a person bought a new car for $22000. for each consecutive year after that, the value of the car depreciated by 5%. how much would the car be worth in the year 2005, to the nearest hundred dollars

Answer 1

To the nearest hundred dollars, the car will be worth $17,900 by 2005

Explanation:

Firstly, we need to write the depreciation equation

We have this as:

V = I(1 - r)^t

V is the present value which is what we want to calculate

I is the initial value, the amount the cad was bought which is $22,000

r is the rate of change which is 5% = 5/100 = 0.05

t is the time difference which is 2005-2001 = 4

Substituting all these into the depreciation equation, we have it that

V = 22,000(1 -0.05)^4

V = $17,919.1375

To the nearest hundred dollars, that would be;

$17,900