Question

Using the balanced reaction 2Al2O3 → 4Al + 3O2 determine the moles of Aluminum Oxide, Al2O3 produced when 85.5 grams of Aluminum Al is produced.

molar masses: Al2O3 = 85.962 O2= 31.998 Al = 26.982

A 1.58 mol

B 8.95 mol

C 6.34 mol

D 1.67 mol

Answer 1

The correct option is option;

A. 1.58 mol

Step-by-step explanation:

The given balanced chemical reaction is presented as follows;

2Al₂O₃ → 4Al + 3O₂

The given mass of Al produced = 85.5 grams

The given molar mass of Al₂O₃ = 85.962 g/mol

The given molar mass of O₂ = 31.998 g/mol

The given molar mass of Al = 26.982 g/mol

`We \ note \ that \ the \ number \ of \ moles, \ n = (Mass )/(Molar \ mass)`

For the given produced Al, n = 85.5 g/(26.982 g/mol) ≈ 3.169 moles

From the given reaction, we have;

2 moles of Al₂O₃ produces 4 moles of Al

∴ 2/4 moles of Al₂O₃ produces 4/4 = 1 mole of Al

2/4 × 3.169 = 1.5845 moles of Al₂O₃ produces 1 × 3.169 = 3.169 moles of Al

∴ 1.5845 ≈ 1.58 moles of Al₂O₃ produces 3.169 moles of Al ≡ 85.5 grams of Al

The correct option is approximately 1.58 moles of Al₂O₃.