Question

What is the output of the following code?

int x = 6, y = 3, z=24, result=0;

result = 2*((z/(x-y))%y+10);

cout<< result<

Answer 1

The output is 24

Step-by-step explanation:

Given

The above code segment

Required

The output

We have (on the first line):

`x = 6`

`y = 3`

`z=24`

`result=0`

On the second line:

`result = 2*((z/(x-y))\%y+10)`

Substitute the value of each variable

`result = 2*((24/(6-3))\%3+10)`

Solve the inner brackets

`result = 2*((24/3)\%3+10)`

`result = 2*(8\%3+10)`

8%3 implies that, the remainder when 8 is divided by 3.

The remainder is 2

So:

`result = 2*(2+10)`

`result = 2*12`

`result = 24`

Hence, the output is 24