Question

Is urgent What is the equation of the line, in point-slope form, that goes through (2, -1)

and is perpendicular to y = 5x + 3?
A. Y+ 1 = 5(x - 2)
O B. y-1--5(x-2)
C. »+1-- *(x-2)
O D. v-2-- }(x+1)

Answer 1

c. y + 1 = -⅕(x - 2)

Explanation:

To write the equation in point-slope form, we need to know the slope (m) and coordinates of a point the line passes through.

The equation would be in the form of y - b = m(x - a).

(a, b) = (2, -1)

Since the line is perpendicular to y = 5x + 3, the slope will be the negative reciprocal of 5 which is -⅕

m = -⅕.

Substitute a = 2, b = -1, and m = -⅕ into y - b = m(x - a).

Thus:

y - (-1) = -⅕(x - 2)

y + 1 = -⅕(x - 2)