Answer:
596
Explanation:
Each term of the arithmetic sequence is 9 greater than the previous term.
Since the first term is 29, then 29+9 = 38, the second term in the sequence. Likewise, the third term, 47, is 9 greater than the previous term, 38. 47 is also 2(9) greater than the first term, 29.
Therefore, finding the 64th term in the sequence would be the same thing as adding 9 to the first term (29) a total of n-1, or 64-1 times. Instead of adding, one can simply multiply 29 by 63, since 64-1 = 63.
29 + 63(9)
= 29 + 567
= 596
So, the 64th term of the arithmetic sequence is 596.