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How to solve for (8n^2 p)^-3?
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2 votes
How to solve for (8n^2 p)^-3?

User Zeratas
by
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1 Answer

6 votes

Answer:

8 / n^6·p^3

Explanation:

8n^-6·p^-3

do not leave negative exponents in the numerator

8 / n^6·p^3

User Amoebe
by
7.0k points
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