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PLZ HELP ASAP BRANILIEST!!!! Seven hundred people are gathered in a trapezoidal park with bases measuring 50 yards and 90 yards and a height of 50 yards.

Find the population density of the park.

The population density of the park is ______ people per square yard.

Find the population density if the bases and height are halved.


The population density of the park if the bases and height are halved is
________people per square yard.

1 Answer

4 votes

Answer:

0.2, 0.8

Explanation:

The area of the park is 0.5h(b1 + b2), where h is the height, b1 is the first base, and b2 is the other base.

Plug the values in:

Area = 0.5(50)(50+90) = 0.5(50)(140) = (50)(70) = 3500

Since 700 people are in the park, there is 700/3500 = 0.2 people per square yard.

If the bases and height are halved, the new area is:

Area = 0.5(25)(25+45) = (35)(25) = 875

The new population density is 700/875 = 0.8 people per square yard.

User Paul S Chapman
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