Question

Find the coordinates of point P witch cuts line segment AB into two parts with a ratio of 3:8

point a : (-15,18) POint B (7,7)

Answer 1

Explanation:

So we'll take the ratio of 3:8 to mean 3 to 8 , which is 11 total parts.

since we know that part, and we can see that the x coordinate goes from -15 to 7, which is a total of 22 and that y goes from 18 to 7, which is a total of 11 then we know that we can just break up each into their 3:8 ratios

3:8=11 for the y component

6:16=22 for the x component

so subtract 3 from the B point for the y or add 3 to the A point , either works here, Let's go from B so y = 10 (7+3) and x = 1 (7-6)

So a point at (1,10) will be on the line and at a ratio of 3:8 :)