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Use the distance that these 9 students skimmer cars traveled in inches to calculate the MIDDLE 50%

468, 376, 540, 198, 230, 531, 281, 426, 346

a. 458 - 353.3
b. 255.5 - 499.5
c. 281 - 468
d. 230 - 531

User ThP
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1 Answer

4 votes

9514 1404 393

Answer:

b. 255.5 to 499.5

Explanation:

The middle 50% is the range between the first and third quartiles. In this group of 9 numbers, the first quartile is the average of numbers 2 and 3 when the numbers are listed from smallest to largest.

first quartile = (230 +281)/2 = 255.5 . . . . . . matches answer choice B

The third quartile is the average of numbers 7 and 8:

third quartile = (468 +531)/2 = 499.5 . . . . . also matches answer choice B

The middle 50% is 255.5 to 499.5.

_____

When I put the numbers in order, I get ...

198 230 ^ 281 246 376 426 468 ^ 531 540

^ indicates that the quartile here is the average of the adjacent numbers

bold indicates the median (2nd quartile)

User Horse SMith
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