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Calculate the mass percent of hydrogen in 70 g of C4H8O3?​

1 Answer

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Answer:

7.14%

Step-by-step explanation:

From the question,

percentage by mass hydrogen in C₄H₈O₃ (h) = mass of hydrogen present in C₄H₈O₃(m)/molar mass of C₄H₈O₃ (m')

h = (m'/m)×100..................... Equation 1

Given: m' = (14×4)+(1×8)+(16×3) = 56+8+48 = 112 g, m = (1×8) = 8 g

Substitute these values into equation 1

h = (8/112)×100

h = 7.14%.

Hence the percentage of hydrogen in 70 g of C₄H₈O₃ is 7.14%

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