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If each letter of the alphabet is worth two more than its preceding letter, where A is the first number and equals 1, B is the second number and equals 3,… and Z is the twenty-sixth which equals ….. What
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If each letter of the alphabet is worth two more than its preceding letter, where A is the first number and equals 1, B is the second number and equals 3,… and Z is the twenty-sixth which equals …..

What does Z equal?

User Brian Deacon
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The answer would be 49 because you just have to add 2 to each number as you go through the alphabet and when you do that it gets you to 49
User DiogoNeves
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