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PLS HELP URGENT

In triangle PQR.
Sis the point on PR such that angle RSQ = 90°
RQ = 14 cm
RS -- 10 cm
SP - 5 cm
Work out the length of PQ.

PLS HELP URGENT In triangle PQR. Sis the point on PR such that angle RSQ = 90° RQ-example-1

2 Answers

3 votes

PQ=11

PS^2+SR^2=QR^2

PS^2+PS^2=PQ^2

User Natesan
by
3.3k points
2 votes

9514 1404 393

Answer:

11 cm

Explanation:

The law of cosines can be helpful here. In order to find PQ, we must know the cosine of the angle R. Fortunately, SOH CAH TOA reminds us it is ...

Cos = Adjacent/Hypotenuse

cos(R) = 10/14 = 5/7

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The law of cosines gives us the relation ...

PQ^2 = PR^2 +QR^2 -2·PR·QR·cos(R)

PQ^2 = 15^2 +14^2 -2(15)(14)(5/7) = 121

PQ = √121 = 11

The length of PQ is 11 cm.

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Alternate solution

This can be solved using the Pythagorean theorem twice.

QS^2 = QR^2 -SR^2 = 14^2 -10^2 = 96

PQ^2 = PS^2 +QS^2 = 5^2 +96 = 121

PQ = √121 = 11

User Seetha
by
4.0k points