Answer:
15.5 g of MnO
Step-by-step explanation:
The reaction is:
MnO₂ + 2NaCl + 2H₂SO₄ → Cl₂ + MnSO₄ + Na₂SO₄ + 2H₂O
We use the Ideal Gases Law to determine the moles of produced chlorine
P . V = n . R .T
We convert T° to Abs. value → 22°C + 273 = 295K
We convert Torr to atm → 710 Torr . 1atm /760 Torr = 0.934 atm
We replace: 10 L . 0.934 atm = n . 0.082 . 295K
( 10 L . 0.934 atm ) / (0.082 . 295K) = n → 0.386 moles
As the NaCl and the acid are in excess, we assume the MnO is the limiting reactant, and ratio is 1:1. so:
0.386 moles of chlorine came from 0.386 moles of MnO
We convert moles to mass: 0.386 . 40.3g/mol = 15.5 g