Question

Find the magnitude and direction of the vector.
<-10, 13>

Answer 1

Use the formula for magnitude of vector, which is
`m = √(a^2 + b^2)`.

`m = √((-10)^2 + 13^2) = 16.401` units

In terms of direction, you can see that it is in the second quadrant because of a negative x-value and positive y-value. If you are looking for the angle of the vector, you need to use the formula,Ф =
`arctan(y/x)`. But because the x, value is negative, the rule is that we add π to this value.

Plug in the values:

arctan(13/-10) + π = 127.56° or 2.226 radians