Question

What is the electric field strength of a point charge of 10 uC at a distance of 5 cm away?

Answer 1

E = 3.6 x 10⁷ N/C

Step-by-step explanation:

The electric field strength due to a point charge is given by the following formula:

`E = (kq)/(r^2)\\\\`

where,

E = Electrical Field Strenght = ?

k = Colomb's Constant = 9 x 10⁹ Nm²/C²

q = magnitude of charge = 10 μC = 1 x 10⁻⁵ C

r = distance = 5 cm = 0.05 m

Therefore,

`E = ((9\ x\ 10^9\ Nm^2/C^2)(1\ x\ 10^(-5)\ C))/((0.05\ m)^2)`

E = 3.6 x 10⁷ N/C