Answer:
71820 J
Step-by-step explanation:
From the question given above, the following data were obtained:
Mass (M) = 1.05 Kg
Initial Temperature (T₁) = 23 °C
Final temperature (T₂) = 99 °C
Heat (Q) required =?
Next, we shall determine the change in temperature. This can be obtained as follow:
Initial Temperature (T₁) = 23 °C
Final temperature (T₂) = 99 °C
Change in temperature (ΔT) =?
ΔT = T₂ – T₁
ΔT = 99 – 23
ΔT = 76 °C
Finally, we shall determine the heat required. This can be obtained as follow:
Mass (M) = 1.05 Kg
Change in temperature (ΔT) = 76 °C
Specific heat capacity (C) of aluminum = 900 J/KgºC
Heat (Q) required =?
Q = MCΔT
Q = 1.05 × 900 × 76
Q = 71820 J
Thus, 71820 J heat energy is required.