Question

[This is the stem]

When 2 moles of Mg3N2 are allowed to react, how many moles of H20 also react?
Mg, Na(s) + 6H20(1)
3Mg(OH)2(s) + 2NH3(g)
1 mole
4 moles
6 moles
8 moles
12 moles

Answer 1

12 moles of water (E)

Step-by-step explanation:

The first step is to see that the equation is balanced. It is now, but you did something strange to the Mg3N2.

Mg3N2(s) + 6H20(l) ======> 3Mg(OH)2(s) + 2NH3(g)

What the equation is telling you is that 1 mol of Mg3N2 requires 6 moles of water for the reaction to occur.

So 2 mols of Mg3N2 would require 6*2 mols of water to react.

The answer is 12 moles of water