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In triangle NOP p equals 600 inches angle P equals 96° and angle N equals 64° what is the area of triangle NOP to the nearest 10th of a square inch?

User XurajB
by
4.8k points

2 Answers

5 votes

Answer:Area

55637.81

55637.8

Area≈55637.81≈55637.8

Explanation:

User Hurrtz
by
4.6k points
4 votes

9514 1404 393

Answer:

55,637.8 square inches

Explanation:

We can find side n using the Law of Sines:

n/sin(N) = p/sin(P)

n = p(sin(N)/sin(P)) = 600·sin(64°)/sin(96°)

n ≈ 542.246913 . . . . inches

The angle O is ...

O = 180° -N -P = 180° -64° -96° = 20°

Then the area is ...

A = 1/2·np·sin(O)

A = (1/2)(542.246913 in)(600 in)·sin(20°) ≈ 55,637.81008 in²

The area of ∆NOP is about 55,637.8 in².

In triangle NOP p equals 600 inches angle P equals 96° and angle N equals 64° what-example-1
User Partyelite
by
5.4k points
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