Question

Calculate the mass of 3.57 mol of magnesium nitrate, Mg(NO3)2.

Answer 1

529.50g

Step-by-step explanation:

Molar mass find by looking at the periodic table and add all the molar mass of the chemicals together

Mg=24.30g

N=14.01g

O=16.00g

Mg(NO3)2=24.30+(14.01+16.00x3)x2=148.32g/mol

148.32x3.57=529.50g