Answer:
pH = 2 and pOH = 12
Step-by-step explanation:
Given [OH⁻] = 1 x 10⁻¹²M
pOH = -log[OH⁻] = -log(1 x 10⁻¹²) = - ( -12 ) = 12
pH + pOH = 14 => pH = 14 - pOH = 14 - 12 = 2
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