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Jennifer drew the graph of f(x) = 2x2 + 4x.

Matt drew the graph of f(x) = 2(x + 1)2 on the same coordinate plane.

Compare the graphs that Jennifer and Matt drew by completing the statements.


Jennifer’s graph is vertically shifted
from Matt’s graph.

Jennifer’s graph is horizontally shifted
from Matt’s graph.

Jennifer’s graph is
Matt’s graph.

Which graph has a vertex that is a maximum?

User Aston
by
4.7k points

2 Answers

4 votes

Answer:

Compare the graphs that Jennifer and Matt drew by completing the statements.

* ) Jennifer’s graph is vertically shifted

2 units down

from Matt’s graph.

** ) Jennifer’s graph is horizontally shifted

0 units left or right

from Matt’s graph.

*** ) Jennifer’s graph is

the same shape as

Matt’s graph.

**** ) Which graph has a vertex that is a maximum?

Neither Jennifer’s nor Matt’s

Explanation:

CORRECT on EDGE November 2021

User Sean Nilan
by
5.3k points
3 votes

9514 1404 393

Answer:

(a) Jennifer’s graph is vertically shifted from Matt’s graph.

neither graph has a maximum

Explanation:

Jennifer's equation can be put into vertex form as ...

f(x) = 2(x^2 +2x +1) -2

f(x) = 2(x +1)^2 -2 . . . . . . vertex at (-1, -2)

Compared to Matt's graph, Jennifer's will be shifted down 2 units.

__

Both graphs open upward, so the vertices are minimums. Neither graph has a vertex that is a maximum. (The vertex on Matt's graph is the maximum of the two vertices.)

Jennifer drew the graph of f(x) = 2x2 + 4x. Matt drew the graph of f(x) = 2(x + 1)2 on-example-1
User Hanseh
by
5.0k points