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A mercury in barometer shows a height of 70cm.What height would be shown in the barometer at the same place if water density 1.0×10³kg/m³ is used(denssity of mercury=13600kgm-³)​

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Answer:

P = d g h pressure due to density of liquid of height h

d1 g h1 = d2 g h2 since P1 equals P2

d1 h1 = d2 h2 and the density of Hg is 13.6 times that of water

h2 = (d1 / d2) * h1 = 13.6 * 70 cm = 952 cm or 9.52 m

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