Question

A city currently has 33,000 residents and is adding new residents steadily at the rate of 1800 per year. If the proportion of residents who remain after t years is given by S(t) = 1/(t + 1), what is the population of the city six years from now? (Round your answer to the nearest integer.)

Answer 1

43,800 Residents

Explanation:

First you would turn this into an equation,

Y=1800x+33000

Once you have it into equation form you would then substitute 6 in for x. This is because x represents how many years. This will get this function.

Y=1800(6)+33000

Now you would simplify and get the answer 43,800 residents.

Answer 2

The population of the city six years from now is 43,800 residents.

The population P(t) after t years is given by the formula:

P(t) = Initial population + Rate of growth * t

In this case, the initial population is 33,000, and the rate of growth is 1,800 per year. Therefore, the formula becomes:

P(t) = 33,000 + 1,800t

To find the population six years from now t = 6 into the formula:

P(6) = 33,000 + 1,800 * 6

P(6) = 33,000 + 10,800

P(6) = 43,800

So, the population of the city six years from now is 43,800 residents.