Answer:
Reaction
Mg+H2SO4 ----》MgSO4+H2
so calculate the moles of magnesium first
moles of magnesium = given mass of mg/molar mass of magnesium
moles = 4/24.30
moles = 0.1646
One mole of magnesium produces one mole of magnesium sulphate
so 0.1646 moles of mg will produce 0.1646 moles of MgSO4
Mass of MgSO4 = 0.1646× 120.366
MgSO4 = 19.81 gm
conclusion the mass of magnesium sulphate that would be obtained from 4g of
magnesium is 19.81 gm!!
I d k it's right or wrong but i tried :)