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Write the equations of 2 straight lines which are perpendicular to y = -3x +0.5.

User Jumanne
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Answer:

y = (1/3)x + 7

y = (1/3)x - 15

These are two examples out of an unlimited number of possibilities.

Explanation:

The slope of this given line is -3. Any new line perpendicular to this one is the negative reciprocal of -3: 1/3.

The slope-intercept form is y = mx + b. Here m = 1/3, so the revised form is

y = (1/3)x + b.

Two straight lines perpendicular to the given line are easily found by selecting two different values for b:

y = (1/3)x + 7

y = (1/3)x - 15

User Paul Van Den Dool
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