Question

Type the slope-intercept equation

of the line that passes through
the points (3,-2) and (6,4).
y = [? ]x + []

Answer 1

y = 2x - 8

Explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m =
`(y_(2)-y_(1) )/(x_(2)-x_(1) )`

with (x₁, y₁ ) = (3, - 2) and (x₂, y₂ ) = (6, 4)

m =
`(4+2)/(6-3)` =
`(6)/(3)` = 2, then

y = 2x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (6, 4 ), then

4 = 12 + c ⇒ c = 4 - 12 = - 8

y = 2x - 8 ← equation of line

Answer 2

y=2x-8

Explanation:

y=Mx+k

Plug in(3,-2)(6,4)

3m+k=-2

6m+k=4

First function multiply by 2,we got:

6m+2k=-4

6m+k=4

k=-8

Y=Mx-8

Plug in any points that is in the question, I use(6,4)

4=6m-8

m=2

Y=2x-8