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The range of y = - 32x ^ 2 + 90x + 3

User Vjdhama
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2 Answers

5 votes

Answer:

y ≤ 66.28 -> -∞

Explanation:

y = a (x-h)² + k ... (h,k): vertex

y = - 32x² + 90x + 3

= -32 (x² - (90/32)x + (90/64)²) + (3 + (32)*(90/64)²)

= -32 (x² - 2*(90/64)x + (90/64)²) + (3+63.28) ... 90/64=1.41

= -32 (x - 1.41)² + 66.28

h = 1.41

k = 66.28 .... extremum of y value

y ≤ 66.28 (y is real number)

User ConfusedWarrior
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6 votes

Enter a problem...

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User Faizan
by
3.5k points