Answer:
787.3 g of CO₂
Step-by-step explanation:
The combustion of octane is this one:
2C₈H₁₈ + 25O₂ → 16CO₂ + 18H₂O
2 moles of octane react to 25 moles of oxygen in order to produce 16 moles of CO₂ and 18 moles of water.
The products in combustion reactions are always CO₂ and H₂O. The oxygen is always a reactant.
We convert mass to moles: 255 g . 1mol /114g = 2.24 moles
2 moles of C₈H₁₈ can produce 16 moles of CO₂
Then, 2.24 moles may produce (2.24 . 16)/2 = 17.9 moles of CO₂
We convert moles to mass:
17.9 mol . 44g/mol = 787.3 g of CO₂