Answer:
The percentage rate of decay per year is of 5.19%.
The function showing the mass of the sample remaining after t is

Explanation:
Exponential equation of decay:
The exponential equation for the amount of a substance is given by:

In which A(0) is the initial amount and r is the decay rate, as a decimal.
Every 13 years, its mass decreases by half.
This means that
. We use this to find r. So



![\sqrt[13]{(1-r)^(13)} = \sqrt[13]{0.5}](https://img.qammunity.org/2022/formulas/mathematics/college/9fg0l85md259uze7xs3p97gkankskulpcq.png)




The percentage rate of decay per year is of 5.19%.
The initial mass of a sample of Element X is 520 grams
This means that
. So



The function showing the mass of the sample remaining after t is
