Question

A 2.25 mol sample of oxygen occupies 1.80 L at 25.0°C. What volume will

it occupy with 3.7 moles?

Answer 1

2.96 L

Step-by-step explanation:

We apply the Ideal Gases Law to determine this:

P . V = n . R . T

Firstly we need to know the pressure for the 2.25 moles

P . 1.80L = 2.25 mol . 0.082 L.atm/mol.K . 298K

(We convert T°C to T°K, 25°C + 273 = 298K)

P = (2.25 mol . 0.082 L.atm/mol.K . 298K) / 1.80L

P = 30.5 atm

So now, we apply the pressure value for the new conditions:

30.5 atm . V = 3.7 mol . 0.082 . 298K

V = (3.7 mol . 0.082 . 298K) / 30.5atm = 2.96 L