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How many moles of Ca(NO3)2 are needed to make 1.50 L of a 6.00 molar solution?
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How many moles of Ca(NO3)2 are needed to make 1.50 L of a 6.00 molar solution?

User Philip Dreyer
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1 Answer

4 votes

Answer:

9.0 moles Ca(NO₃)₂

Step-by-step explanation:

from definition of Molarity = moles of solute / volume of solution in liters

=> moles = Molarity x Volume(L) = 6.00 molar x 1.5 liters = 9.0 moles Ca(NO₃)₂

User Amir Gorji
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