Question

100 kg of a mixture that is 28% solids with the remainder water is put into a centrifuge to remove part of the water. The centrifuge runs for a half hour. A mixture that is now 60% solids is removed from the centrifuge and placed in a dryer for an additional hour. The product coming out of the dryer is 98% solids. Determine the following:

a. What is the mass of the mixture added to the dryer?
b. What is the mass of the product removed from the dryer?
c. How much water is removed from the original mixture by the centrifuge?
d. How much water is removed by the dryer?

Answer 1

a. 46.7kg is the mass of the mixture added to the dryer.

b. 28.57kg is the mass removed from the dyer

c. 53.3kg are removed by the centrifuge.

d. 18.13kg are removed by the dryer

Step-by-step explanation:

As the 28% of the mixture is solids in 100kg, initially we have 28kg of solids.

a. Assuming in the supernatant there is no remaining solid and as the mixture is now 60% (60/100) solids:

2k8g solids *( 100 / 60) = 46.7kg is the mass of the mixture added to the dryer.

b. As the mass removed from the dyer is 98% of solids:

28kg Solids * (100 / 98) = 28.57kg is the mass removed from the dryer

c. As the original mass is 100kg and the mass removed 46.7kg:

100 - 46.7 =

53.3kg are removed by the centrifuge

d. The difference in mass between mass removed by the dryer and the added is:

46.7kg - 28.57kg =

18.13kg are removed by the dryer