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What is the volume of 3.00 × 10 20atoms in an aluminum block? The density of aluminum is 2.70 g/cm 3 .

User Ollien
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Answer:


V=4.98x10^(-3)cm^3

Step-by-step explanation:

Hello there!

In this case, according to the given atoms of aluminum, it is possible for us to calculate the mass via the Avogadro's number and its atomic mass of 27.0 g/mol:


m_(Al)=3.00x10^(20)atoms Al*(1molAl)/(6.022x10^(23)atomsAl) *(27.0gAl)/(1mol)=0.0135gAl

Noe, given the density of the Al, we can calculate the volume as shown below:


d=m/V\\\\V=m/d\\\\V=0.0135g/(2.70g/cm^3)\\\\V=4.98x10^(-3)cm^3

Best regards!

User Zword
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