Question

HELP ME ASAP PLEASEEEE

If 3.25 moles of Ar occupies 100.L at a certain temperature and pressure, what volume does 14.15 moles of Ar occupy?

Answer 1

`V_2=435.4L`

Step-by-step explanation:

Hello there!

In this case, for this gas problem, we can use the Avogadro's law as a way to understand the volume-mole behavior as a directly proportional relationship:

`(V_2)/(n_2)=(V_1)/(n_1)`

Thus, given the initial and final moles and the initial volume, we obtain the following final volume:

`V_2=(V_1n_2)/(n_1) =(100.L*14.15mol)/(3.25mol)\\\\V_2=435.4L`

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