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A 0.200 L sample of neon gas is cooled at 270 K is cooled until the volume is 0.180 L. What is the new temperature?

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Answer:

243 K.

Step-by-step explanation:

From the question given above, the following data were obtained:

Initial volume (V₁) = 0.2 L

Initial temperature (T₁) = 270 K

Final volume (V₂) = 0.18 L

Final temperature (T₂) =?

The final temperature of the gas can be obtained by using the Charles' law equation as illustrated below:

V₁ / T₁ = V₂ / T₂

0.2 / 270 = 0.18 / T₂

Cross multiply

0.2 × T₂ = 270 × 0.18

0.2 × T₂ = 48.6

Divide both side by 0.2

T₂ = 48.6 / 0.2

T₂ = 243 K

Thus, the final temperature of the gas is 243 K

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