Question

The velocity of 200kg object changes from 10m/s to 22m/s in 12 sec.what is the force on the accelerated object?

a)100n
b)200n
c)600n
d)500n​

Answer 1

• Initial velocity (u) = 10 m/s
• Final velocity (v) = 22 m/s
• Time (t) = 12 s
• Mass (m) = 200 Kg
• Let the acceleration be a.
• By using the equation of motion,

v = u + at, we have

• 22 m/s = 10 m/s + 12 s × a
• or, 22m/s - 10 m/s = 12 s × a
• or, 12 m/s = 12 s × a
• or, a = 1 m/s^2
• Let the force be F.
• We know, F = ma
• Therefore, the force on the accelerated object (F)
• = ma
• = (200 × 1) N
• = 200 N

Answer:

b) 200 N

Hope you could understand.

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