Answer:
We accept H₀. The information is not enough to reject H₀
Explanation:
In 2011
Mean for the cost of a private room in a nursing home μ = 239 $/day
Sample in 2021
265 283 266 366 243 334 213 266 140 276 292
average = x = 267,64
Standard deviation s = 56,31
We assume a normal distribution. Random sample, sample size and the fact that population standard deviation is unknown drive to develop a t -student two-tail test at 5 % of significance level
n = 11 then degree of freedom df = n - 1 df = 10
Then from t-student table df = 10 and α = 0,05 α/2 = 0,025
we get t(c) = 2,228
Hypothesis Test:
Null Hypothesis H₀ x = μ = 239
Alternative Hypothesis Hₐ x ≠ μ
To calculate t(s)
t(s) = ( x - μ ) / s/ √n
t(s) = ( 267,64 - 239 ) / 56,31/√10
t(s) = 28,64 *3,16 / 56,31
t(s) = 1,61
Comparing t(s) and t(c)
t(s) < t(c)
Then t(s) is in the acceptance region we accept H₀ . We did´t found enough evidence to reject H₀