Question

In the decomposition of KCLO3, how many moles of KCL are formed in the reaction that produces 0.05 moles of O2?

Answer 1

0.033 moles of KCl are formed.

Step-by-step explanation:

The reaction that takes place is:

• 2KClO₃ → 2KCl + 3O₂

To solve this problem we need to convert 0.05 moles of O₂ into moles of KCl, to do so we use the stoichiometric coefficients of the balanced reaction:

• 0.05 mol O₂ *
  `(2molKCl)/(3molO_2)` = 0.033 mol KCl

If 0.05 moles of O₂ are produced, then 0.033 moles of KCl are formed as well.