Question

Julie has picked 10× 3 silver three red three green and one orange she now has a 12% chance of picking which color

Answer 1

None of the colors

Explanation:

The given parameters can be represented as:

`Silver = 3`

`Red = 3`

`Green = 3`

`Orange =1`

`Total = 10`

Required

Which has a probability of 12%

To do this, we calculate the probability of each color.

This is calculated as:

`P(Color) = (Color)/(Total)`

So, we have:

`P(Silver) = (Silver)/(Total)`

`P(Silver) = (3)/(10)`

Express as percentage

`P(Silver) = 30\%`

`P(Red) =(Red)/(Total)`

`P(Red) =(3)/(10)`

Express as percentage

`P(Red) =30\%`

`P(Green) = (Green)/(Total)`

`P(Green) = (3)/(10)`

Express as percentage

`P(Green) = 30\%`

`P(Orange) = (1)/(10)`

`P(Orange) = 0.1`

Express as percentage

`P(Orange) = 10\%`

So, we have:

`P(Silver) = 30\%`

`P(Red) =30\%`

`P(Green) = 30\%`

`P(Orange) = 10\%`

From the above calculations, none of the colors have a probability of 12%.