Answer:
(1.962 ; 2.578) ;
There is a 95% chance that the true population mean of the number of children of all couples who have been married for 7 years lies within the interval (1.962 ; 2.578);
(1.865 ; 2.675);
There is a 99% chance that the true population mean of the number of children of all couples who have been married for 7 years lies within the interval (1.8646 ; 2.6754)
Explanation:
Given the data :
0, 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 5
Using calculator :
Mean, xbar = 2.27
Standard deviation, s = 1.219
Sample size = 60
Confidence interval :
Xbar ± Margin of error
Margin of Error = Zcritical * s/sqrt(n)
Zcritical at 95% = 1.96
Margin of Error = 1.96 * 1.219/ sqrt(60) = 0.3084
Lower boundary = (2.27 - 0.3084) = 1.962
Upper boundary = (2 27 + 0.3084) = 2.578
(1.962 ; 2.578)
There is a 95% chance that the true population mean of the number of children of all couples who have been married for 7 years lies within the interval (1.962 ; 2.578)
C.) 99% confidence interval :
Xbar ± Margin of error
Margin of Error = Zcritical * s/sqrt(n)
Zcritical at 99% = 2.576
Margin of Error = 2.576 * 1.219/ sqrt(60) = 0.4054
Lower boundary = (2.27 - 0.4054) = 1.8646
Upper boundary = (2.27 + 0.4054) = 2.6754
(1.865 ; 2.675)
There is a 99% chance that the true population mean of the number of children of all couples who have been married for 7 years lies within the interval (1.8646 ; 2.6754)