Solution :
Method I : SL method
Cost of equipment = $ 500,000
Salvage value = $ 50,000
Expected life = 5 years
Depreciation =
![$\frac{\text{(cost of equipment - salvage value)}}{\text{expected life}}$](https://img.qammunity.org/2022/formulas/business/college/ncqhl0c1xsfdbg6u77wpua7p63efends3h.png)
![$=((500,000-50,000))/(5)$](https://img.qammunity.org/2022/formulas/business/college/64z5t3p1ej611nb1tkre5zwclayrey0079.png)
= 90,000
Therefore, the
is $ 90,000 using the SL method.
Method II : DDB method
Cost of equipment = $ 500,000
Expected life = 5 years
So, calculating the
at the end of the year 1 is :
Depreciation =
![$\text{cost of equipment }* \frac{2}{\text{expected life}}$](https://img.qammunity.org/2022/formulas/business/college/3w3a9hpxpwehup2qtqxkly2ct0sqs8f136.png)
![$=500,000* (2)/(5)$](https://img.qammunity.org/2022/formulas/business/college/u56wlbz09cs5r73b6w10k69nveao51umpi.png)
= $ 200,000
So the book value at the end of the year 1 = $ 500,000 - $ 200,000
= $ 300,000
Now calculating the
at the end of the year 2 is :
Depreciation =
![$\text{book value at the end of year 1 }* \frac{2}{\text{expected life}}$](https://img.qammunity.org/2022/formulas/business/college/p8uvhrqpox7hmqdokdaq2fx1maotmxhoh1.png)
![$=300,000* (2)/(5)$](https://img.qammunity.org/2022/formulas/business/college/g2ixg5ycabv28qhj9qbls0wnrmuhot15uu.png)
= $ 120,000
Therefore, the
value is $ 120,000 using the DDB method.
Method III : 150% DB method
Cost of equipment = $ 500,000
Expected life = 5 years
So, calculating the depreciation in year 1 is :
Depreciation =
![$\text{cost of equipment }* \frac{1.5}{\text{expected life}}$](https://img.qammunity.org/2022/formulas/business/college/yohggkqjdwzuihuir1abz03mulpbg0ijlk.png)
![$=500,000* (1.5)/(5)$](https://img.qammunity.org/2022/formulas/business/college/6yd88slfceqj70od9er61xa7iathey6z83.png)
= $ 150,000
So the book value at the end of the year 1 = $ 500,000 - $ 150,000
= $ 350,000
Now calculating the depreciation in year 2 is :
Depreciation =
![$\text{book value at the end of year 1 }* \frac{1.5}{\text{expected life}}$](https://img.qammunity.org/2022/formulas/business/college/8wp1ym8680f3y81yv1a9x1bcbikcuq3unj.png)
![$=350,000* (1.5)/(5)$](https://img.qammunity.org/2022/formulas/business/college/7avxzncbk7avshbohfkszbdo7ke82shfet.png)
= $ 105,000
Therefore, the
value is $ 105,000 using the 150% DB method.