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The equation of a line a is given by 3y=x+12 - Find line c that is perpendicular to line a and passes through the point (6, -8)

The equation of a line a is given by 3y=x+12 - Find line c that is perpendicular to line a and passes through the point (6, -8)
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The equation of a line a is given by 3y=x+12

- Find line c that is perpendicular to line a and passes through the point (6, -8)

User Dennis Anikin
by
9.1k points

1 Answer

3 votes

Answer:

Y+8=-3(x-6)

Explanation:

User Simpleengine
by
7.9k points
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