Question

Jennie is standing 52 km away from the Volcano and the volcano is 2.4 km high. Assuming Makayla and the base of the volcano are at the same elevation above sea level, what is the angle of elevation from Makayla to the top of the volcan??

Answer 1

Solution :-

Since Jennie is standing away so,

`\sf \: \tan( \arctan) = (2.4)/(52)`

=> 2.64⁰

Answer 2

9514 1404 393

Answer:

2.64°

Explanation:

The relevant trig relation is ...

Tan = Opposite/Adjacent

Here, the side of the right triangle in this geometry that is adjacent to the angle of elevation is the distance to the volcano: 52 km. The side opposite is the height of the volcano: 2.4 km. Then the angle α is found from ...

tan(α) = 2.4/52

α = arctan(2.4/52) ≈ 2.64°

The angle of elevation from Makayla's position is about 2.64°.