Question

A car starts from rest and attains a velocity of 9km/h in 5 seconds . Calculate acceleration and the displacement covered in that time

Answer 1

Acceleration is 0.5 m/s² and the distance covered is 6.25 m.

Explanation:

Given that,

Initial speed, u = 0

Final speed, v = 9 km/h = 2.5 m/s

Time, t = 5 seconds

We need to find the acceleration and the displacement covered in that time. Acceleration = rate of change of velocity

So,

`a=(v-u)/(t)\\\\a=(2.5-0)/(5)\\\\a=0.5\ m/s^2`

Distance d can be calculated using third equation of motion.

`d=(v^2-u^2)/(2a)\\\\d=(2.5^2-0^2)/(2* 0.5)\\\\d=6.25\ m`

So, acceleration is 0.5 m/s² and the distance covered is 6.25 m.