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Find the distance between y= 2/3x+4 and y=2/3x-1 1. Round your answer to the nearest tenth. The distance is about units.​

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Answer:

12.5

Explanation:

y= 2/3x+4 and y=2/3x-1 1 are parallel: slope 1 = 2/3 = slope 2

the distance of line 1 and line 2 is the segment length of perpendicular line intercept two parallel lines. In other words, the distance between two parallel lines in the plane is the minimum distance between any two points lying on the lines. It equals the perpendicular distance from any point on one line to the other line.

equation of the perpendicular line pass the y intercept of line 1: y=2/3x+4 (0,4) is y = -3/2x + 4, which intercept with line 1 at (0,4)

solve the intercept of perpendicular line with line 2: get (6.9 , -6.4)

y=-3/2x + 4 and y=2/3x-1 1 (you should be able to solve this part by self)

distance of (0,4) and (6.9,-6.4): √(6.9-0)²+(-6.4-4)² = √155.77 = 12.48 ≈ 12.5

Find the distance between y= 2/3x+4 and y=2/3x-1 1. Round your answer to the nearest-example-1
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