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P is the incenter of △JKL. Find m∠JKP.
& can you please explain

P is the incenter of △JKL. Find m∠JKP. & can you please explain-example-1

1 Answer

7 votes

Answer:

∠JKP = 35°

Explanation:

since P is the incenter, then lines to incenter bisect the corner angles:

7x - 6 = 5x + 4

subtract 5 x from both sides of the equation:

2x - 6 = 4

add 6 to each side:

2x = 10

divide both sides by 2:

x = 5

∠KJP = 7(5) - 6 = 29°

∠LJP = 5(5) + 4 = 29°

then ∠KJL = 29° + 29° = 58°

∠KLJ = 26° + 26° = 52°

∠JKL = 180° - 58° - 52° = 70°

∠JKP = 1/2 ∠JKL = 1/2(70°) = 35°

there might be a more direct way about it but this was the least confusing way I know to explain it.

User Zachary Kuhn
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