Answer:
c. 80%
Step-by-step explanation:
Given;
load raised by the machine, L = 360 N
distance through which the load was raised, d = 0.2 m
effort applied, E = 50 N
distance moved by the effort, e = 1.8 m
The efficiency of the machine is calculated as follows;
![Efficiency = ( 0utput \ work )/(1nput \ work) * 100\% \\\\Efficiency = (Load \ * \ distance \ moved \ by \ load )/(Efort \ * \ distance \ moved \ by \ effort) * 100\%\\\\Efficiency = (360 * 0.2)/(50 * 1.8) * 100\%\\\\Efficiency =80\%](https://img.qammunity.org/2022/formulas/physics/high-school/o1joas2bsj7ta0goelgk63slp8ibxfn20m.png)
Therefore, the efficiency of the machine is 80%