Question

1. You have a large flashlight

which uses 6 V of electricity. If
the current in the flashlight is 2
A, what is the resistance of the
light bulb?

Answer 1

3 Ω

Step-by-step explanation:

The resistance can be found by using the equation for Ohms law which is

V = IR

V is the voltage

I is the current

R is the resistance

`r = (v)/(i) \\`

We have

`r = (6)/(2) = 3 \\`

We have the final answer as

3 Ω

Hope this helps you