Answer:
H0 : σ² = 10
H1 : σ² ≠ 10
X² = 20.124
Pvalue = 0.064776
there is significant evidence to conclude that the rebound lengtb of rockfall down a slope is not 10m²
Explanation:
Given the data:
10.94 13.71 11.38 7.26 17.83 11.92 11.87 5.44 13.35 4.90 5.85 5.10 6.77
Using a calculator ;
The sample variance, s² = 16.77
α = 0.10
The null and alternative hypothesis :
H0 : σ² = 10
H1 : σ² ≠ 10
The test statistic :
X² = [(n - 1)*s² ÷ σ²]
s² = 16.77
n = sample size = 13 ; s²
X² = [(13 -1)*16.77 ÷ 10
X² = (12 * 16.77) / 10
X² = 201.24 / 10
X² = 20.124
The Pvalue using a Pvalue calculator ; degree of freedom (df) = 13 - 1 = 12
Pvalue = 0.064776
Pvalue < α ; Hence we reject the null
Hence, there is significant evidence to conclude that the rebound lengtb of rockfall down a slope is not 10m²